A thin uniform wire is bent to form the two equal sides AB and AC of triangle ABC, where
AB = AC = 5 cm. The third side BC, of length 6cm, is made from uniform wire of twice the linear mass density of the first. The distance of centre of mass from A is :
A
cm
B
cm
C
cm
D
cm
Text Solution
Verified by ExpertsThe correct answer is:
A
y cm = 
= 
Distance from A = (4 – 
= 
)
A = (4 – 
= 
)
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